The formula of atoms vibration energy:

If you know that energy of a vibrating atom is quantized, then which of the following is wrong?

Which of the following can represent an energy of vibration?

The least value of an atom’s vibration energy.

The atom’s energy is quantized means that its values are:

A particle that has no mass and carries a quantum of energy.

An atom absorbs a photon with frequency ${10}^{12}Hz$, the change in the atom’s energy will …. ($h={6.626\times10}^{-34}\ J/Hz$).

The minimum frequency for incident light that is able to eject electrons from an element’s atoms.

The ejection of electrons when an electromagnetic radiation falls on an object is called:

Electrons are ejected from an atom only if the frequency of the incident radiation is greater than a certain minimum value is called:

When an ultraviolet radiation falls on a negative charged zinc board, it ejects an electron from zinc because:

The photon was discovered by:

If the threshold frequency of a metal was $4.4\times{10}^{14}Hz$ What is the needed energy to eject the electron from the surface of the metal?

Einstein explained the photoelectric effect by saying that visible light consists of quantized bundles of energy called:

The product of Planck’s constant and the frequency of the photon is called:

The energy of a photon is:

What is the energy of a photon, if its frequency is

$1\times{10}^{15}Hz$

? Knowing that Planck’s constant is

$6.63\times{10}^{-34}J.s$

?

Wave A has frequency of ${10}^{23}Hz$, and wave B has a wavelength of ${10}^{-12}$. The right comparison between the two energies are:

If the wave frequency increases, then…

Which of the following frequencies has the lowest energy?

An incident photon with frequency $f_0$ falls on a metal with work function of ${hf}_0$. As a result, the electron will:

The figure shows the relationship between the kinetic energy and frequency of a metal. What point represents threshold frequency?

For electromagnetic waves, which of these following statements is correct?

If the energy of a photon falling on a metal surface was 4.7eV, and work function is 3.7eV, then the kinetic energy of ejected electrons is:

A photon with a frequency of

$110\times{10}^{14}Hz$

falls on a surface with a threshold frequency of

$10\times{10}^{14}Hz$

. What is the kinetic energy? Knowing that Planck’s constant is

${6.63\times10}^{-34}J.s$

Energy of an electron moving across an electric potential difference of one volt is called: